Problem
Determine the final height (H) of an object when the only force acting on it is gravity (F = mg), given its initial velocity (Vₒ), initial height (Hₒ), and final velocity (V).Solution
We can justify the solution by considering the law of conservation of mechanical energy in the absence of friction. In this scenario, the total mechanical energy of the object remains constant, which includes both kinetic energy and potential energy.The law of conservation of mechanical energy can be expressed as follows
E0 = E
Where:
E0 is the initial mechanical energy of the object, and
E is the final mechanical energy of the object.
Initial mechanical energy consists of the sum of initial kinetic energy
K0= ½mv₀²
and initial potential energy
U0= mgh₀
The final mechanical energy consists of the sum of the final kinetic energy
The final mechanical energy consists of the sum of the final kinetic energy
K = ½mv²
and final potential energy
U = mgh.
So, the law of conservation of mechanical energy can be expressed as:
½mv² + mgh = ½mv₀² + mgh₀
See the following algebraic transformation of the equation to find the expression for the unknown value:
So, the law of conservation of mechanical energy can be expressed as:
½mv² + mgh = ½mv₀² + mgh₀
See the following algebraic transformation of the equation to find the expression for the unknown value:
½mv² + mgh = ½mv₀² + mgh₀,
mv² + 2mgh = mv₀² + 2mgh₀,
v² + 2gh = v₀² + 2gh₀,
v²/(2g) + h = v₀²/(2g) + h₀,
h = v₀²/(2g) + h₀ - v²/(2g) .
v² + 2gh = v₀² + 2gh₀,
v²/(2g) + h = v₀²/(2g) + h₀,
h = v₀²/(2g) + h₀ - v²/(2g) .
Calculation
Enter the following values:
No comments:
Post a Comment